題目:

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

思路:

找到可以符合兩數加總等於 target 的index 並回傳.

最簡單就是利用迴圈檢查所有組合可能,並將其逐一檢查.

若符合規則就將索引建立為一個 array 回傳.

 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
class Solution {
    public int[] twoSum(int[] nums, int target) {
        
        for(int i = 0;i < nums.length ; i++){
            for(int j=i+1 ; j<nums.length;j++){
                if(nums[i] + nums[j] == target)
                    return new int[]{i,j};
            }
        }
        return new int[]{0,0};
        
    }
}
arrow
arrow
    文章標籤
    leetcode Easy
    全站熱搜

    Lung-Yu,Tsai 發表在 痞客邦 留言(0) 人氣()